Here are some example of Lawsin's Mathematical Red Herring:
1+2+3+4(1+2+3+4) = x
(4!)(4!) = x
(4!)^2 = x
(24)^2 = x
x = 576
1+2+3+4(1+2+3+4) = x
1+2+3+4(10) = x
(1*10)+(2*10)+(3*10)+(4*10) = x
10+20+30+40 = x
x = 100
Simplification:
1+2+3+4(1+2+3+4) = x
(10)(10) = x
x = 100
Solutions from PEMDAS / BODMAS:
1+2+3+4(1+2+3+4) = x
1+2+3+4(10) = x
1+2+3+40 = x
x = 46
Lawsin's MDASFE:
1+2+3+4(1+2+3+4) = x
[1*(1+2+3+4)] + [2*(1+2+3+4)] + [3*(1+2+3+4)] + [4*(1+2+3+4)] = x
x = 100
INVALID RED HERRING:
prove: 0/0 = 2
(100-100)/(100-100) = x
[(10^2)-(10^2)]/[10(10-10)] = x
[(10-10)(10+10)]/[10(10-10)]= x
20/10 = x
x = 2
